Question

6.19 парни и девочки помагите с вопросом пожалуйста ​

Answer 1

Ответ:

Всё ниже.

Объяснение:

$\frac{x {}^{6} + x {}^{4} }{x {}^{4} + x {}^{2} } = \frac{x {}^{4}(x {}^{2} + 1) }{x {}^{2}(x {}^{2} + 1) } = \frac{x {}^{4} }{x {}^{2} } = x {}^{2}$

$\frac{x {}^{6} - x {}^{8} }{x {}^{4} - x {}^{2} } = \frac{x {}^{6} (1 - x {}^{2}) }{x {}^{2}(x {}^{2} - 1) } = \frac{x {}^{6} (1 - x)(1 + x)}{x {}^{2}(x - 1)(x + 1) } = \frac{ - x {}^{6}(x - 1)(x + 1) }{x {}^{2}(x - 1)(x + 1) } = \frac{ - x {}^{6} }{x {}^{2} } = - x {}^{4}$

$\frac{m {}^{7} - m {}^{10} }{m {}^{9} - m {}^{3} } = \frac{m {}^{7} (1 - m {}^{3}) }{m {}^{3}(m {}^{6} - 1) } = \frac{m {}^{7} (1 - m {}^{3} ) }{m {}^{3} (m {}^{3} - 1)(m {}^{3} + 1) } = \frac{ - m {}^{7} ( m {}^{3} - 1) }{m {}^{3}(m {}^{3} - 1)(m {}^{3} + 1) } = -\frac { - m {}^{7} }{m {}^{3}(m {}^{3} + 1) } = - \frac{m {}^{4} }{m {}^{3} + 1}$

$\frac{a {}^{6} - a {}^{4} }{a {}^{3} + a {}^{2} } = \frac{a {}^{4} (a {}^{2} - 1) }{a {}^{2}(a + 1) } = \frac{a {}^{4}(a - 1)(a + 1) }{a {}^{2}(a + 1) } = \frac{a {}^{4}(a - 1) }{a {}^{2} } = a {}^{2} (a - 1) = a {}^{3} - a {}^{2}$

Удачи☘.