Question

sinπ/6-4cosπ/6+tgπ/6-5ctgπ/3​

Answer 1

Ответ:

1

$\sin( \frac{\pi}{6} ) - 4\cos( \frac{\pi}{6} ) + tg( \frac{\pi}{6} ) - 5ctg( \frac{\pi}{3} ) = \\ = \frac{1}{2} - 4 \times \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{3} - \frac{5 \sqrt{3} }{3} = \\ = \frac{1}{2} - 2 \sqrt{3} - \frac{4 \sqrt{3} }{3} = \frac{3 - 12 \sqrt{3} - 8 \sqrt{3} }{6} = \frac{3 - 20 \sqrt{3} }{6}$

2

$\cos( \frac{\pi}{2} ) + 9 \sin( \frac{\pi}{2} ) - ctg( \frac{\pi}{4} ) - 7tg(0^{\circ} ) = \\ = 0 + 9 - 1 - 0 = 8$

3

$\sqrt{3} \cos( \frac{\pi}{6} ) + 2ctg( \frac{\pi}{3} ) - 11ctg( \frac{\pi}{4} ) = \\ = \sqrt{3} \times \frac{ \sqrt{3} }{2} + 2 \times \frac{ \sqrt{3} }{3} - 11 = 1.5 + \frac{2 \sqrt{3} }{3} - 11 = \frac{2 \sqrt{3} }{3} - 9.5$

4

$ctg( \frac{\pi}{2} ) - 5 \sin( \frac{\pi}{3} ) + 6 \cos( \frac{\pi}{3} ) - tg( \frac{\pi}{6} ) = \\ = 0 - 5 \times \frac{ \sqrt{3} }{2} + 6 \times \frac{1}{2} - \sqrt{3} = \\ = \frac{ - 5 \sqrt{3} + 6 - 2 \sqrt{3} }{2} = \frac{6 - 7 \sqrt{3} }{2}$