Предмет: Химия, автор: DariyaSolovyeva

Помогите составить электронный баланс следующего уравнения:
Fe + 4HNO3(разб) = Fe(NO3)3 + NO + 2H2O

Ответы

Автор ответа: ValeraDavay

0

Fe + 4HNO3(разб) = Fe(NO3)3 + NO + 2H2O

Fe(0) -3e = Fe(+3) |1
N(+5)+3e = N(+2) |1

Автор ответа: Persikova

0

2Fe + 4HNO3 = Fe(NO3)3+3NO + 2H2O

Fe(0) -3e =Fe(+3) /3/6/2

N(+5) +2e = N(+3)/2/6/3

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