Question

4. Решите уравнение: [46]
1
+ 7 = 1,06
200
(y +4
4)+
пж ​

Answer 1

$(y + 4 \frac{1}{200} ) \div 7 = 1.06 \\ (y + \frac{801}{200} ) \times \frac{1}{7} = 1.06 \\ \frac{200y + 801}{200} \times \frac{1}{7} = 1.06 \\ \frac{200y + 801}{1400} = 1.06 \\ 200y + 801 = 1484 \\ 200y = 1484 - 801 \\ 200y = 683 \\ y = \frac{683}{200} = 3 \frac{83}{200} = 3.415$