Question

решите уравнение (x - 3)^2 = 16.​

Answer 1

$\left ( x-3 \right )^2=16\Leftrightarrow \left ( x-3-4 \right )\left ( x-3+4 \right )=0\Leftrightarrow \left ( x-7 \right )\left ( x+1 \right )=0\\ x=\left \{ -1;7 \right \}$