Question

разложить на множителии​

Answer 1

в)

$0.001 + z {}^{3} = \frac{1}{1000} + z {}^{3} = \frac{1}{1000} \times (1 + 1000z {}^{3} ) = \frac{1}{1000} \times (1 + 10z)(1 - 10z + 100z {}^{2} )$

г)

$c {}^{2} + 10c + 25 = c {}^{2} + 2 \times c \times 5 + 5 {}^{2} ) = (c + 5) {}^{2}$

$2mn - 2mk + 3n - 3k = 2m(n - k) + 3(n - k) = (n - k)(2m + 3)$