Question

сроочччноо помогите пожалуйста умоляю​

Answer 1

Ответ:

x1= –1

x2= –4

Объяснение:

$\\ \frac{2x {}^{2} + 3x + 1}{(x + 1)(x - 3)} = 1$

$\\ \frac{2x {}^{2} + 3x + 1}{x {}^{2} - 3x + x - 3} = 1$

$\\ \frac{2x {}^{2} + 3x + 1}{x {}^{2} - 2x - 3} = 1$

2х²+3х+1=х²–2х–3

2х²+3х+1–х²+2х+3=0

х²+5х+4=0

Д=b²–4ac=5²–4×1×4=25–16=9

$\\ x1 = \frac{ - b + \sqrt{d} }{2a} = \frac{ - 5 + \sqrt{9} }{2} = \\ = \frac{ - 5 + 3}{2} = \frac{ - 2}{2} = - 1$

$\\ x2 = \frac{ - b - \sqrt{d} }{2a} = \frac{ - 5 - \sqrt{9} }{2} = \\ = \frac{ - 5 - 3}{2} = \frac{ - 8}{2} = - 4$