Предмет: Английский язык, автор: kungurovamaria51

Complete the questions. Use what, where,
who, when, how or which.
What's your teacher's name?
Mrs Kempton
1 do you live?
In Manchester.
2
's your best friend?
Karen.
3
......'s your sister's birthday?
July
old is your brother?
He's ten.
4.
5 ......'s that?
It's an egg.
6 ...... food do you like best - pizza or
hamburgers?
Pizza
's my book?
It's here.
8 ...... are these?
They're sandwiches.​

Ответы

Автор ответа: slyuda1955
2

2 who

3 when

4 what

5 what

6 where

7 what

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Предмет: Физика, автор: Аноним
Формулы даны просто посчитайте. В электрической цепи постоянного тока заданы сопротивления: R1=60 Ом, R2=120 Ом, R3=60 Ом, R4= 40 Ом. Задан также ток на третьем участке i3=2A. Определить : общее сопротивление всей цепи, токи и напряжение на всех участках и общее потребление мощности.

Формулы :
R=R1+R2,3+R4
R2,3=R2,R3/R2+R3
U3=IR=U2
R=IU

Решили уже вот ответ если попадется тоже самое:
1. Находим напряжение 3 участке по закону ома для участка цепи: U=I*R=2*40=80В
2. Так как при последовательном соединении сопротивлений токи на всех участках одинаковы, то ток в 2А действует и на первый участок, отсуда по тому же закону находим напряжение на 1 участке U=2*60 = 120В
3. Находим общее сопротивление второго участка: R=(R2*R3)/(R2+R3)=(120*60)/(120+60)=40 Ом
Так как при параллельном включении сопротивлений напряжения одинаковы, то находим напряжение для 3 участка, а ток как мы знаем при последовательном соединении 2 А: U = 40*2 = 80 В

4. Общее сопротивление R=60+40+40=140 Ом
5. Общее напряжение цепи: 80+120+80 = 280В
6. Общая потребляемая мощность: P=U*I = 280*2=560 Вт
или же через сопротивление: P=U^2/R=280^2/120=560 Вт