Question

найти производную
f(х) =Корень4х+1 дробь х-3

Answer 1

$f= \frac{ \sqrt{4x+1} }{x-3}$
$f ' =( \frac{ \sqrt{4x+1} }{x-3}) ' = \frac{ \frac{1}{2 \sqrt{4x+1} }*4(x-3)-1* \sqrt{4x+1} }{(x-3)^2} =$
$\frac{ 2x-6-( \sqrt{4x+1})^2 }{(x-3)^2* \sqrt{4x+1} } =\frac{ 2x-6-4x-1 }{(x-3)^2* \sqrt{4x+1} }=\frac{ -2x-7 }{(x-3)^2* \sqrt{4x+1} }$