Question

х²+ 16х + 64 = 0
помогите пж​

Answer 1

$x^{2} +16x+64=0$

$a=1;b=16;c=64$

$D=b^{2} -4ac=16^{2} -4*64*1=256-256=0$

$x=\frac{-b}{2a} =\frac{-16}{2} =-8$

Ответ: $x=-8$

Answer 2

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