Question

Номер 4 и 5. Какое сможете.

Answer 1

(х-3)/3+4<0
x-3+12<0
x+9<0
x<-9
при х (-∞;-9)

Answer 2

$\frac{x-3}{3}+4\ \textless \ 0 \\ \frac{x-3}{3}\ \textless \ -4 \\ x-3\ \textless \ -4*3 \\ x\ \textless \ -12+3 \\ x\ \textless \ -9$
x∈]-∞;-9[