Question

Комплексные Числа

1) 4-3i/7-2i
2) 7i/2+i

Answer 1

$frac{4-3i}{7-2i} = frac{(4-3i)(7+2i)}{(7-2i)(7+2i)}=frac{28-21i+8i-6i^2}{49-4i^2}=frac{28-13i+6}{49+4}=cfrac{34-13i}{53}$

$frac{7i}{2+i} = frac{7i(2-i)}{(2+i)(2-i)} =frac{14i-7i^2}{4-i^2} =frac{14i+7}{4+1} =frac{14i+7}{5} =2.8i+1.4$