Question

Помогите пожалуйста ❤️




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Answer 1

Ответ:

..,........................

Answer 2

1)

$\left( 2\dfrac{1}{3}\right )^2 - \dfrac{4}{9} = \left( \dfrac{7}{3} \right)^2 - \dfrac{4}{9} = \dfrac{49}{9} - \dfrac{4}{9} = \dfrac{45}{9} = 5$

2)

$\left( 1\dfrac{1}{2}\right )^3 + \dfrac{5}{8} = \left( \dfrac{3}{2}\right )^3 + \dfrac{5}{8} = \dfrac{27}{8} + \dfrac{5}{8} = \dfrac{32}{8} = 4$

3)

$3\dfrac{5}{9} + \left( \dfrac{2}{3}\right )^2 = \dfrac{32}{9} + \dfrac{4}{9} = \dfrac{36}{9} = 4$

4)

$\left( \dfrac{1}{2} \right)^4 + 3\dfrac{1}{4} = \dfrac{1}{16} + \dfrac{1}{4} + 3 = \dfrac{1}{16} + \dfrac{4}{16} + 3 = \dfrac{5}{16} + 3 = 3\dfrac{5}{16}$

5)

$7\dfrac{2}{5} - \left( \dfrac{2}{5} \right)^2 = 7 + \dfrac{2}{5} - \dfrac{4}{25} = 7 + \dfrac{10}{25} - \dfrac{4}{25} = 7 + \dfrac{6}{25} = 7\dfrac{6}{25}$

6)

$9 - \left( 1\dfrac{1}{3} \right)^2 = 9 - \left( \dfrac{4}{3} \right)^2 = 9 - \dfrac{16}{9} = 7 + \dfrac{18}{9} - \dfrac{16}{9} = 7 \dfrac{2}{9}$