Question

 квадратный корень из 3 tg x+1=0

Answer 1

$sqrt{3} tgx+1=0\ \ tgx=- frac{1}{sqrt{3}} \ \ x=-arctg( frac{1}{sqrt{3}} )+ pi n,n in mathbb{Z}\ \ boxed{x=- frac{pi}{6}+pi n,n in mathbb{Z} }$