Предмет: Геометрия, автор: maksnazar234

дано ABCD-ромб, AB=20сантеметров,Ac: BD=3:4 найти: площадь ромба ABCD

Ответы

Автор ответа: bobby66

Пусть АС = 6Х, а BD= 8X
M- точка пересечения диагоналей.
Тогда AM=3X, BM=4X. По теореме Пифагора AB= 5X
Следовательно Х=20/5=4.
Тогда AC=6*4=24, BD=8*4=32
А площадь ромба равна половине произведений диагоналей.
S=1/2*24*32=384 кв.см.

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