Question

Решите пожалуйста, желательно с решением

Answer 1

Ответ:

$1) {2}^{1 - 3x} = {2}^{4} \\ 1 - 3x = 4 \\ - 3x = 3 \\ x = - 1$

$2) {3}^{3 - x} = {3}^{4} \\ 3 - x = 4 \\ - x = 1 \\ x = - 1$

$3) {8}^{ - 4 - x} = {8}^{3} \\ - 4 - x = 3 \\ - x = 7 \\ x = - 7$

$4) {16}^{x - 9} = {2}^{ - 1} \\ {2}^{4(x - 9)} = {2}^{ - 1} \\ 4x - 36 = - 1 \\ 4x = 35 \\ x = \frac{35}{4} \\ x = 8.75$

$6) {4}^{x - 13} = {2}^{ - 1} \\ {2}^{2(x - 13)} = {2}^{ - 1} \\ 2x - 26 = - 1 \\ 2x = 25 \\ x = 12.5$

$7) {25}^{x - 4} = {5}^{ - 1} \\ {5}^{2(x - 4)} = {5}^{ - 1} \\ 2x - 8 = - 1 \\ 2x = 7 \\ x = 3.5$

$8) {81}^{x - 3} = {3}^{ - 1} \\ {3}^{4(x - 3)} = {3}^{ - 1} \\ 4x - 12 = - 1 \\ 4x = 11 \\ x = 2.75$

$9) {( \frac{1}{4} )}^{2x - 19} = \frac{1}{64} \\ {4}^{ - (2x - 19)} = {4}^{ - 3} \\ - 2x + 19 = - 3 \\ - 2x = - 22 \\ x = 11$