Question

ХЕЛПАНИТЕ ПОБРАТСКИ​

Answer 1

Объяснение:

$px^2-5x+8=0\ \ \ \ x_1=4*x_2\ \ \ \ p=?\\\\x_{1,2}=\frac{5б\sqrt{25-32p} }{2p}\ \ \ \ \Rightarrow\\ \frac{5+\sqrt{25-32p} }{2p}=4*(\frac{5-\sqrt{25-32p} }{2p})\ |*2p\\5+\sqrt{25-32p} =4*(5-\sqrt{25-32p)}\\5+\sqrt{25-32p} =20-4\sqrt{25-32p} \\5*\sqrt{25-32p} =15\ |:5\\\sqrt{25-32p} =3\\(\sqrt{25-32p})^2 =3^2\\25-32p=9\\32p=16\ |:32\\p=0,5.$

Ответ: p=0,5.