Question

2cos2x+√3=0 помогитее

Answer 1

$2\cos2x+\sqrt{3} =0$

$2\cos2x=-\sqrt{3}$

$\cos2x=-\dfrac{\sqrt{3} }{2}$

$2x=\pm\arccos\left(-\dfrac{\sqrt{3} }{2}\right)+2\pi n$

$2x=\pm\dfrac{5\pi}{6}+2\pi n$

$\boxed{x=\pm\dfrac{5\pi}{12}+\pi n,\ n\in\mathbb{Z}}$