Предмет: Физика, автор: roganovaanzela

1,43 кг воздуха занимают при 0

0С объем 0,5м

3

.Воздуху сообщили

некоторое количество теплоты и он изобарно расширился до объема

0,55м

3

. Найти совершенную работу, количество поглощенного тепла,

изменения температуры и внутренней энергии воздуха.
Напишите Дано, решение,анализ пожалуйста

roganovaanzela: спасчибо большое

roganovaanzela: спасибо большое

Ответы

Автор ответа: danialsheenoda6

Ответ:

Объяснение:

давление газа P=mRT/MV=(1,43*8,31*273)/(29*10^(-3)*0,5)=2,24*10^5Па, изменение его объема dV=0,05м^3. работа газа A=PdV, из уравнения М-К PdV=m/M*RdT, отсюда dT=MPdV/mR. изменение внутренней энергии dU=5/2*mR*dT/M=5/2*PdV. количество теплоты Q=dU+A.

roganovaanzela: дано решение анализ?

danialsheenoda6: Дано:
m=1,43 кг
T=0C=273K
M=29*10^(-3) кг/моль
V=0.5 м^3
dV=0,05м^3
Найти: A-? Q-? dU-?dT -?

roganovaanzela: спасибо большое

danialsheenoda6: Пожалуйста

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