Question

пожалуйста помогите срочно ​

Answer 1

1.

а)

$\frac{25p^{4}q}{100p^{5}q} =\frac{1}{4p}$

б)

$\frac{ab(y+3)}{a^{2}b(y+3)} =\frac{1}{a}$

2.

а)

$\frac{1}{3a^{3}}-\frac{2}{5a^{5}} =\frac{5a^{2}}{15a^{5}} -\frac{6}{15a^{5}} =\frac{5a^{2}-6}{15a^{5}}$

б)

$\frac{x-y}{xy} -\frac{x-z}{xz} =\frac{z(x-y)}{xyz} -\frac{y(x-z)}{xyz} =\frac{xz-yz}{xyz}-\frac{xy-yz}{xyz}=\frac{xz-yz-xy+yz}{xyz} =\frac{xz-xy}{xyz} =\\\\=\frac{x(z-y)}{xyz} = \frac{z-y}{yz}$

3.

а)

$(\frac{n^{2}}{10m})^{3} =\frac{n^{6}}{1000m^{3}}$

б)

$(-\frac{3x^{2}}{2y^{3}} )^{3}=-\frac{27x^{6}}{8y^{9}}$

4.

а)

$\frac{x^{2}-xy}{y}*\frac{y^{2}}{x} =\frac{x(x-y)}{y} *\frac{y^{2}}{x} =y(x-y)=xy-y^{2}$

б)

$\frac{2ab}{3c^{2}d} :\frac{2cd^{2}}{9ab} :\frac{a^{2}b}{c^{3}d} =\frac{2ab}{3c^{2}d}*\frac{9ab}{2cd^{2}} *\frac{c^{3}d}{a^{2}b} =\frac{2ab*9ab*c^{3}d}{3c^{2}d*2cd^{2}*a^{2}b} =\frac{18a^{2}b^{2}c^{3}d}{6c^{3}d^{3}a^{2}b} =\frac{3b}{d^{2}}$