Question

Розв'язати систему методом підстановки
{x-3y=5;
{4x+2y=41.​

Answer 1

$\left \{ {{x-3y=5} \atop {4x+2y=41}} \right. \\\left \{ {{x=5+3y} \atop {4(5+3y)+2y=41}} \right.\\20+12y+2y=41;\\14y=21;\\y=1.5;\\x=5+3*1.5=9.5;$

Answer 2

$\left \{ {{x-3y=5} \atop {4x+2y=41}} \right.$

$\left \{ {{x=5+3y} \atop {4*(5+3y) + 2y = 41}} \right.$

$20 + 12y + 2y = 41\\14y = 21\\y = 1.5$

$x = 5 + 3*1.5 = 9.5$