Предмет: Химия, автор: egorkaa63

Нужно решить:
вычислить массу кислорода, требуемого для получения 16г оксида железа(3) из железа.
решать нужно с составлением пропорции и записей:
По усл-ю ....
По р-ии .....

Ответы

Автор ответа: ZANGI
0
)                  x г                    16 г    
            4Fe   +  3O₂      =       2Fe₂O₃                 
             3•32 г/моль   2• 160 г/моль
X= 3•32•16/160•2 = 4,8 гОтвет: m(O₂) = 4.8 г
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