Question

Пользуясь формулой (1+х)^n ~~ 1+nx

Answer 1

$1.002^5\approx 1+5*0.002= 1+0.01=1.01$

$0.997^4\approx1+4*(-0.003)=1-0.012=0.988$

$2.004^3=(2*1.002)^3=2^3*1.002^3\approx 8*(1+3*0.002)=8*1.006=8.048$

$3.01^5=(3*(1+\dfrac{1}{300}))^5=3^5*(1+\dfrac{1}{300})^5\approx 3^5*(1+5*\dfrac{1}{300})=243*(1+\dfrac{1}{60})=243+\dfrac{81}{20}=247.05$