Question

Алгебра. Решение показательных уравнений и неравенств

Answer 1

1

7^x = 9^x

(7/9)^x = 1

x = 0

2

5*3^x - 3*5^x = 0

5*3^x = 3*5^x

3^(x-1) = 5^(x - 1)

(3/5)^(x - 1) = 1

x - 1 = 0

x = 1

3

2^(x+3) - 3^x = 3^(x + 1) - 2^x

2^(x + 3) + 2^x = 3^(x+1) + 3^x

2^x*(2^3 + 1) = 3^x*(3 + 1)

2^x * 9 = 3^x * 4

(2/3)^x = 4/9 = (2/3)^2

x = 2

Answer 2

Ответ:

1)x=0

2)x=1

3)x=2

Объяснение:

1)(7/9)ˣ=(7/9)⁰

x=0

2)5*3^x=3*5^x

5*(3/5)^x=3

(3/5)^x=3/5

(3/5)^x=(3/5)^1

x=1

3)2^x*2^3-3^x=3^x*3-2^x

8*2^x-3^x=3*3^x-2^x

8*2^x+2^x-3^x=3*3^x

8*2^x+2^x=3*3^x+3^x

9*2^x=3*3^x+3^x

9*2^x=3*3^x+1*3^x

9*2^x=(3+1)*3^x

9*2^x=4*3^x

9*2^x/3^x=4*3^x/3^x

9*(2/3)^x=4

(2/3)^x=4/9

(2/3)^x=(2/3)^2

x=2