Question

Якщо g(x)= $\frac{1}{x}$, a f(x)=$\frac{1}{x^2+1}$, то y=f(g(x))=?

Answer 1

$g(x)=\frac{1}{x},\ f(x) = \frac{1}{x^2+1} \\\\y=f(g(x))=\dfrac{1}{(\frac{1}{x})^2+1 }=\dfrac{x^2}{x^2+1}$