Question

найдите производную функции у=1/х(2х+1)

Answer 1

y=f`*g+f*g`

y=(1/x)`*(2x+1)+(1/x)*(2x+1)` 

y=-2x^-1+-x^-2+2/x

Answer 2

y'=u'v+v'u

$y'=-frac{1}{x^{2}} cdot 2x+1+2cdot frac{1}{x} =\= -frac{2x}{x^{2}}-frac{1}{x^{2}}+frac{2}{x}=\=-frac{2}{x}-frac{1}{x^{2}}+frac{2}{x}=\=-frac{1}{x^{2}}$