Question

СРООЧНО АЛГЕБРА!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$\frac{16k + 8}{k - 9} - \frac{k - 8}{k - 9} + \frac{8k + 1}{9 - k} = \frac{16k + 8}{k - 9} - \frac{k - 8}{k - 9} - \frac{8k + 1}{k - 9} = \frac{16k + 8 - (k - 8) - (8k + 1)}{k - 9} = \frac{16k + 8 - k + 8 - 8k - 1}{k - 9} = \frac{7k + 15}{k - 9}$