Question

Выручайте ребят!!!
1.$lim_{x to -1} (-8x^{3} -4x+9 x^{2} )$

2.$lim_{x to6} frac{ x^{2} +x-42}{x-6}$

3.$lim_{x to12} frac{ x^{2} -7x+60}{ x^{2} -144}$

Answer 1

  $lim_{xto 1}(-8x^3-4x+9x^2)=-8cdot 1-4cdot 1+9cdot 1=-3\\lim_{xto 6}frac{x^2+x-42}{x-6}=[frac{0}{0}]=lim_{xto 6}frac{(x-6)(x+7)}{x-6}=lim_{xto 6}(x+7)=6+7=13\\lim_{xto 12}frac{x^2-7x+60}{x^2-144}=[frac{144-84+60}{144-144}]=[frac{120}{0}]=infty$

Answer 2

:)