Question

5 /y+y-5/y+3 помогите мне пожалуйста

Answer 1

$\frac{5}{y} + \frac{y-5}{y+3} = \frac{5 (y+3)}{y(y+3)} +\frac{y(y-5)}{y(y+3)} = \frac{(5y + 15) +(y^{2} -5y)}{y^{2}+3y} = \frac{5y + 15 + y^{2} -5y}{y^{2}+3y } =\frac{15+y^{2} }{y^{2}+3y } = 0$

15+y² = 0

y² = -15

y = $\sqrt{-15}$

∅