Question

Пожалуйста решите
И найдите дискриминант

Answer 1

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Answer 2

$\frac{x}{x-2}+\frac{8}{4-x^{2}}-\frac{1}{x+2}=0\\\\\frac{x}{x-2}-\frac{8}{(x-2)(x+2)}-\frac{1}{x+2}=0\\\\\frac{x^{2}+2x-8-x+2 }{(x-2)(x+2)}=0\\\\\frac{x^{2}+x-6}{(x-2)(x+2)}=0\\\\\left \{ {{x^{2}+x-6=0 } \atop {x\neq 2;x\neq-2}} \right.\\\\x^{2}+x-6=0\\\\D=1^{2}-4*(-6)=1+24=25=5^{2}\\\\x_{1}=\frac{-1-5}{2}=-3\\\\x_{2}=\frac{-1+5}{2}=2-neyd\\\\Otvet:\boxed{-3}$