Question

ПОМОГИТЕ ПРЕОБРАЗОВАТЬ В ПРОИЗВЕДЕНИЕ!!!

Answer 1

$1+2sin\alpha =2*(\frac{1}{2} +sin\alpha )=2*(sin\frac{\pi }{6} +sin\alpha )=2*2*sin(\frac{\pi }{12} +\frac{\alpha }{2} )*cos(\frac{\pi }{12} -\frac{\alpha }{2} )=\\\\=4*sin(\frac{\pi }{12} +\frac{\alpha }{2} )*cos(\frac{\pi }{12} -\frac{\alpha }{2} )$

Ответ:  $4*sin(\frac{\pi }{12} +\frac{\alpha }{2} )*cos(\frac{\pi }{12} -\frac{\alpha }{2} )$