Question

решите пожалуйста!) задание:вычислите 2/3√12 и 1/4√27

Answer 1

файл

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6e6b627a7deb5246f659acd3a90c92db.doc

Answer 2

$frac{2}{3sqrt{12}}=frac{2cdotsqrt{12}}{3sqrt{12}cdotsqrt{12}}=frac{2cdotsqrt{4cdot3}}{3cdot12}=frac{2cdot2sqrt{3}}{3cdot12}=frac{4sqrt{3}}{36}=frac{sqrt{3}}{9}=frac{1}{9}sqrt{3}$

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$frac{1}{4sqrt{27}}=frac{1cdotsqrt{27}}{4sqrt{27}cdotsqrt{27}}=frac{sqrt{27}}{4cdot27}= frac{sqrt{9cdot3}}{108}=frac{3sqrt{3}}{108}=frac{sqrt{3}}{36}=frac{1}{36}sqrt{3}$

6e6b627a7deb5246f659acd3a90c92db.doc