Question

1) 12х²- 5х - 2 = 0
2) х² – 6х +9 = 0

Answer 1

$1)\; \; 12x^2-5x-2=0\; \; ,\; \; D=25+4\cdot 12\cdot 2=121\; ,\\\\x_1=\frac{5-11}{24}=\frac{-6}{24}=-\frac{1}{4}\\\\x_2=\frac{5+11}{24}=\frac{16}{24}=\frac{2}{3}\\\\\\2)\; \; x^2-6x+9=0\; \; ,\; \; \; (x-3)^2=0\; \; ,\; \; x-3=0\; \; ,\; \; x=3$