Question

Решить систему: x в^2-2xy+y в^2=49
                                 x-3y=1

Answer 1

x^2-2xy+y^2=49
x-3y=1
(x-y)^2=49
x=1+3y
(1+3y-y)^2=49
(1+2y)^2=49
1+2y=7
y=3
x=10
1+2y=-7
y=-4
x=-11