Question

8х в квадрате+х-9=0?

Answer 1

Ответ:

D = 1 - 4 * (-9) * 8 = 1 + 288 = 289

x1 = $\frac{-1 + \sqrt{289} }{8 * 2}$ = $\frac{16}{16}$ = 1

x2 = $\frac{-1 - \sqrt{289} }{8 * 2}$ = $\frac{-18}{16}$ = -1,125