Question

Даю 100 баллов срочно решите плиз

Answer 1

$1)\; \; 6x^3-24x=0\; \; ,\; \; 6x\cdot (x^2-4)=0\; ,\\\\6x\cdot (x-2)(x+2)=0\\\\x_1=0\\\\x-2=0\; \; ,\; \; x_2=2\\\\x=2=0\; \; ,\; \; x_3=-2\\\\Otvet:\; \; 0\; ;\; 2\; ;\; -2\; .$

$2)\; \; 25x^3-10x^2+x=0\; \; ,\; \; x\cdot (25x^2-10x+1)=0\; ,\\\\x\cdot (5x-1)^2=0\\\\x_1=0\\\\5x-1=0\; \; ,\; \; x_2=\frac{1}{5}\\\\Otvet:\; \; 0\; ;\; \frac{1}{5}\; .$

Answer 2

$6 {x}^{3} - 24x = 0 \\ 6x( {x}^{2} - 4) = 0 \\ x = 0 \\ {x}^{2} = 4 \\ x_{1} = 0 \\ x_{2/3} =±2$

Ответ: -2, 0, 2

$25 {x}^{3} - 10 {x}^{2} + x = 0 \\ x(25 {x}^{2} - 10x + 1) = 0 \\ x_{1} = 0 \\ (5x)^{2} - 2 \times 5x + 1 = 0 \\ (5x - 1)^{2} = 0 \\ 5x - 1 = 0 \\ 5x = 1 \\ x _{2}= 0.2$

Ответ: 0, 0.2