Question

пожалуйста
без разницы какой вариант ​

Answer 1

Ответ:

A1

$2x^{2} -18=0\\2x^{2}=18 \\x^{2} =9\\x_{1} =3\\x_{2}=-3$

$x^{2} +2x=0\\x(x+2)=0\\x=0\\x=-2$

$4x^{2} =0\\x^{2} =0\\x=0$

$4x^{2} -11=x^{2} -11+9x\\4x^{2} -11-x^{2} +11-9x=0\\3x^{2}-9x=0\\3x(x-3)\\x=0\\x=3$

$x^{2} -2x+1=0\\\sqrt{D} = 4-4\\D=0\\x=\frac{2}{2} =1$