Question

2 задание нужно срочно

Answer 1

$1+2sina=2\cdot (\frac{1}{2}+sina)=2\cdot (sin\frac{\pi}{6}+sina)=\\\\=2\cdot 2\cdot sin(\frac{\pi}{12}+\frac{a}{2})\cdot cos(\frac{\pi}{12}-\frac{a}{2})=4\cdot sin(\frac{\pi}{12}+\frac{a}{2})\cdot cos(\frac{\pi}{12}-\frac{a}{2})$

Answer 2

Ответ:

Объяснение:

Формула: sinx+siny=2sin((x+y)/2)cos((x-y)/2)

0,5=sinπ/6

1=2sinπ/6

1+2sina=2sinπ/6+2sina=2(sinπ/6+sina)=2·2sin((π/6+a)/2)cos((π/6-a)/2)=

=4sin(π/12+a/2)cos(π/12-a/2)