Question

1 задание нужно срочно

Answer 1

$\mathrm{tg}(a+b)=\dfrac{\mathrm{tg}a+\mathrm{tg}b}{1-\mathrm{tg}a\mathrm{tg}b} =\dfrac{-\dfrac{3}{4} +2.4}{1-\left(-\dfrac{3}{4}\right)\cdot2.4} =\dfrac{1.65}{1+1.8} =\dfrac{1.65}{2.8} =\dfrac{165}{280} =\dfrac{33}{56}$

Answer 2

$tga=-\frac{3}{4}=-0,75\; \; ,\; \; tg\beta =2,4\\\\\\tg(a+\beta )=\dfrac{tga+tg\beta }{1-tga\cdot tg\beta }=\dfrac{-0,75+2,4}{1+0,75\cdot 2,4}=\dfrac{1,65}{2,8}=\dfrac{165}{280}=\dfrac{33}{56}$