Question

решите квадратные уравнение неполным способом
1-9х^2=0
2x^2-2x=0

Answer 1

Ответ:

$1-9x^{2} =0\\-9x^{2} =-1\\x^{2} =\frac{1}{9}$⇒  $x=+-\frac{1}{3}$

x=-1/3

x=1/3

$2x^{2} -2x=0\\2x(x-1)=0\\x(x-1)=0\\x=0\\x-1=0$⇒$x=1$

x=0

x=1

Answer 2

1)

$\displaystyle \tt 1-9x^2=0\\\\\displaystyle \tt 1=9x^2\\\\ \displaystyle \tt 9x^2=1\\\\ \displaystyle \tt x^2=\frac{1}{9}\\\\ \displaystyle \tt x=б\sqrt{\frac{1}{9}}\\\\ \displaystyle \tt \bold{x_1=\frac{1}{3}}\\\\ \displaystyle \tt \bold{x_2=-\frac{1}{3}}$

2)

$\displaystyle \tt 2x^2-2x=0\\\displaystyle \tt 2x(x-1)=0\\\\\displaystyle \tt x(x-1)=0\\ \displaystyle \tt \bold{x_1=0}\\\\\displaystyle \tt x-1=0\\\displaystyle \tt \bold{x_2=1}$