Question

11-х дробная черта х-1= х-4

Answer 1

Ответ:

Объяснение:

(11-x)/(x-1) = x-4

(11-x)/(x-1) -(x-4) = 0

(11-x-(x-4)(x-1))/(x-1) =0

(11-x-(x^2-x-4x+4))/(x-1)=0

(11-x-x^2+5x-4)/(x-1)=0

(-x^2+4x+7)/(x-1) = 0

x ≠ 1

-x^2+4x+7 = 0

D = 16+28=44

x = (4±$\sqrt[]{44}$)/2

x = 2 ±$\sqrt[]{11}$