Question

$2x^{4}-8x^{2}-10-x^{4}\sqrt{x}-4x^{2}\sqrt{x}-5\sqrt{x}=0$

Answer 1

Ответ:

Объяснение:

2x⁴-8x²-10-x⁴*√x+4*x²*√x-5*√x=2*(x⁴-4x²-5)+√x*(x⁴-4x²-5)=

(x⁴-4x²-5)*(2+√x)=(x⁴-5x²+x²-5)(2+√x)=(x²(x²-5)+(x²-5))(2+√x)=

=(x²-5)(x²+1)(2+√x).