Question

решите, я тупой чуть-чуть

Answer 1

Ответ:

14-у=0

Объяснение:

Answer 2

$\displaystyle \tt \left \{ {{x=6} \atop {2\cdot6-y+2=0}} \right. \displaystyle \tt \to \left \{ {{x=6} \atop {12-y+2=0}} \right. \to \left \{ {{x=6} \atop {14-y=0}} \right.$

Ответ:

$\displaystyle \tt \left \{ {{x=6} \atop {\boxed{\displaystyle \tt 14-y}=0}} \right.$