Question

Решите пж!!! СРОЧНОООО!!!!!

Answer 1

   $(\frac{1}{x^2}+\frac{1}{y^2}+\frac{1}{x+y}*\frac{2x+2y}{xy})*\frac{x^2y^2}{x^2-y^2}=$

$=(\frac{1}{x^2}+\frac{1}{y^2}+\frac{1*2*(x+y)}{(x+y)*xy})*\frac{x^2y^2}{x^2-y^2}=$

$=(\frac{1}{x^2}+\frac{1}{y^2}+\frac{2}{xy})*\frac{x^2y^2}{x^2-y^2}=$

$=\frac{1*y^2+1*x^2+2xy}{x^2y^2}*\frac{x^2y^2}{x^2-y^2}=$

$=\frac{x^2+2xy+y^2}{x^2y^2}*\frac{x^2y^2}{x^2-y^2}=$

$=\frac{(x+y)^2}{x^2y^2}*\frac{x^2y^2}{x^2-y^2}=$

$=\frac{(x+y)^2*x^2y^2}{x^2y^2*(x^2-y^2)}=$

$=\frac{(x+y)^2}{x^2-y^2}=\frac{(x+y)*(x+y)}{(x-y)*(x+y)}=\frac{x+y}{x-y}$