Question

Решите системы неравенств:
а) 3x+9>0,
x-5<1;
б) 2-у >= 3,
3y-1<=2.

Answer 1

$1)\left \{ {{3x+9>0} \atop {x-5<1}} \right.\\\\\left \{ {{3x>-9} \atop {x<6}} \right.\\\\\left \{ {{x>-3} \atop {x<6}} \right. \\\\Otvet:\boxedx\in(-3;6)$

$2)\left \{ {{2-y\geq3 } \atop {3y-1\leq2 }} \right.\\\\\left \{ {{-y\geq1 } \atop {3y\leq3}} \right.\\\\\left \{ {{y\leq-1 } \atop {y\leq 1}} \right.\Rightarrow y\leq-1\\\\Otvet:\boxedx\in(-\infty;-1]$