Question

Помогите с математикой
Пределы

Answer 1

$\lim\limits_{n\to\infty}\dfrac{6n^3-\sqrt{n^5+1}}{\sqrt{4n^6+3}-n}=\lim\limits_{n\to\infty}\dfrac{6-\sqrt{\dfrac{1}{n}+\dfrac{1}{n^6}}}{\sqrt{4+\dfrac{3}{n^6}}-\dfrac{1}{n^2}}=\dfrac{6}{\sqrt 4}=3$