Question

$\frac{p {}^{2} - 11p + 10 }{20 + 8p - p {}^{2} }$
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Answer 1

$\displaystyle \tt \frac{p^2-11p+10}{20+8p-p^2}=\frac{p^2-p-10p+10}{-p^2+8p+20}=\frac{p(p-1)-10(p-1)}{-p^2+10p-2p+20}=\frac{(p-1)(p-10)}{-p(p-10)-2(p-10)}=\frac{(p-1)(p-10)}{-(p-10)(p+2)}=\frac{(p-1) \cdot (-1)}{p+2}=-\frac{p-1}{p+2}=\boxed{\bold{\frac{1-p}{p+2}}}$