Question

Найдите корень уравнения 28(1-4x) = 7(3x+5).​

Answer 1

$\displaystyle \tt 28(1-4x)=7(3x+5)\\ \displaystyle \tt 28-112x=21x+35\\ \displaystyle \tt -112x-21x=35-28\\ \displaystyle \tt -133x=7\\ \displaystyle \tt x=\frac{7}{-137}\\ \displaystyle \tt x=-\frac{1}{19}$