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Answer 1

$\frac{1}{5} +\frac{3}{4} =\frac{1*4}{5*4} +\frac{3*5}{4*5} =\frac{4}{20} +\frac{15}{20} =\frac{4+15}{20} =\frac{19}{20}$

$\\ \\ \\\frac{3}{7} +(1-\frac{5}{7} )=\frac{3}{7} +(\frac{7}{7} -\frac{5}{7} )=\frac{3}{7} +\frac{2}{7} =\frac{5}{7}$

$\frac{2}{15} +(1-\frac{4}{15} )=\frac{2}{15} +(\frac{15}{15} -\frac{4}{15} )=\frac{2}{15} +\frac{15-4}{15}=\frac{2}{15} +\frac{11}{15} =\frac{13}{15}$

$\frac{7}{8} +(1-\frac{1}{8} )=\frac{7}{8} +\frac{7}{8} =\frac{14}{8} =1\frac{6}{8}=1\frac{3}{4}$

$\frac{3}{5} +\frac{1}{15} =\frac{9}{15} +\frac{1}{15} =\frac{10}{15} =\frac{2}{3}$

$\frac{2}{15}-\frac{3}{25} =\frac{2}{15}-\frac{3}{25} =\frac{10}{75} -\frac{9}{75} =\frac{1}{75}$

$\frac{3}{14}+ \frac{5}{7} =\frac{3}{14}+ \frac{10}{14} =\frac{13}{14}$

$\frac{13}{15} +(1-\frac{8}{15} )=\frac{13+15-8}{15} =\frac{20}{15} =1\frac{1}{3}$

$1-\frac{7}{18}+\frac{11}{18} =\frac{18-7+11}{18} =\frac{22}{18} =1\frac{4}{18} =1\frac{2}{9}$

$\frac{6}{11}+\frac{2}{3} =\frac{18}{33} +\frac{22}{33} =\frac{40}{33}=1\frac{7}{33}$

$\frac{2}{3}+(1-\frac{3}{5})=\frac{10}{15} +\frac{15}{15} -\frac{9}{15}=\frac{10+15-9}{15} =\frac{16}{15}=1\frac{1}{15}$

$\frac{3}{4}-(1-\frac{5}{8})=\frac{3}{4}-1+\frac{5}{8}=\frac{6-8+5}{8} =\frac{3}{8}$

$\frac{13}{20} +(1-\frac{1}{5})=\frac{13+20-4}{20} =\frac{29}{20} =1\frac{9}{20}$

$\frac{7}{9} -(1-\frac{4}{5})=\frac{35}{45}-\frac{45}{45}+\frac{36}{45}= \frac{26}{45}$

$\frac{9}{10} +\frac{6}{25} =\frac{45+12}{50} =1\frac{7}{50}$

$\frac{3}{5} +\frac{4}{15}=\frac{9+4}{15}=\frac{13}{15}$

$\frac{3}{4} +\frac{7}{12}=\frac{9+7}{12} =1\frac{4}{12} =1\frac{1}{3}$

$\frac{12}{25}+(1-\frac{11}{15})=\frac{36}{75}+\frac{75}{75} -\frac{55}{75} =\frac{56}{75}$

$1-\frac{7}{9}+\frac{11}{12}=\frac{36-28+33}{36} =\frac{41}{36} =1\frac{5}{36}$

$1-\frac{3}{4} +\frac{3}{5} =\frac{20-15+12}{20} =\frac{17}{20}$