Question

Помогите пжжжжжжжжжжж

Answer 1

$1)\sqrt{4^{2}+0^{2}}=\sqrt{4^{2}} =4\\\\2)\sqrt{0^{2}+(-6)^{2}} =\sqrt{6^{2} } =6\\\\3)\sqrt{5^{2}+(-12)^{2}}=\sqrt{25+144}=\sqrt{169}=\sqrt{13^{2}}=13\\\\4)\sqrt{(-7)^{2}+24^{2}}=\sqrt{49+576}=\sqrt{625}=\sqrt{25^{2}}=25$

$5)\sqrt{10^{2}+(-24)^{2}}=\sqrt{100+576}=\sqrt{676}=\sqrt{26^{2}}=26\\\\6)\sqrt{(\sqrt{21})^{2}+2^{2}}=\sqrt{21+4}=\sqrt{25}=\sqrt{5^{2}}=5\\\\7)\sqrt{(\sqrt{13})^{2}+6^{2}} =\sqrt{13+36}=\sqrt{49}=\sqrt{7^{2}}=7\\\\8)\sqrt{(6\sqrt{2})^{2}+(-6\sqrt{2})^{2}}=\sqrt{72+72}=\sqrt{144}=\sqrt{12^{2}}=12$